-.005x^2+2x+2=0

Solution for -.005x^2+2x+2=0 equation:

-.005x^2+2x+2=0

We add all the numbers together, and all the variables

-0.005x^2+2x+2=0

a = -0.005; b = 2; c = +2;
Δ = b2-4ac
Δ = 22-4·(-0.005)·2
Δ = 4.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{4.04}}{2*-0.005}=\frac{-2-\sqrt{4.04}}{-0.01}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{4.04}}{2*-0.005}=\frac{-2+\sqrt{4.04}}{-0.01}
$